Question

lab questions

1. record your results. (c - 10 marks)

metals	kcl	fe(no₃)₂	cacl₂	na₂co₃	hcl

|cu|
|zn|
|mg|

1. for each single displacement reaction write a balance chemical equation. if there is no reaction, write nr> (k/u - 10 marks)

Explanation:

Step1: Recall metal - activity series

Based on the metal - activity series, metals higher in the series can displace metals lower in the series from their compounds. Also, metals react with acids to produce hydrogen gas if they are more reactive than hydrogen.

Step2: Analyze reactions with Cu

Copper (Cu) is less reactive than potassium (K), iron in $Fe(NO_3)_2$, calcium in $CaCl_2$, and does not react with $Na_2CO_3$ in a single - displacement way. With HCl, Cu is less reactive than hydrogen, so no reaction.

• Cu + KCl → NR
• Cu + $Fe(NO_3)_2$ → NR
• Cu + $CaCl_2$ → NR
• Cu + $Na_2CO_3$ → NR
• Cu+HCl → NR

Step3: Analyze reactions with Zn

Zinc (Zn) is more reactive than iron.

• Zn + $Fe(NO_3)_2$ = $Zn(NO_3)_2$+Fe
• Zn is less reactive than K and Ca, so no reaction with KCl and $CaCl_2$.
• Zn + KCl → NR
• Zn + $CaCl_2$ → NR
• Zn + $Na_2CO_3$ → NR
• Zn + 2HCl = $ZnCl_2$+ $H_2$↑

Step4: Analyze reactions with Mg

Magnesium (Mg) is more reactive than iron, potassium, calcium.

• Mg + 2$Fe(NO_3)_2$ = $Mg(NO_3)_2$+2Fe
• Mg is more reactive than K and Ca, but in aqueous solutions, the reaction is complex due to water involvement. In simple single - displacement considering metal - metal ion, we assume no reaction with KCl and $CaCl_2$ in the context of basic single - displacement.
• Mg + KCl → NR
• Mg + $CaCl_2$ → NR
• Mg + $Na_2CO_3$ → NR
• Mg + 2HCl = $MgCl_2$+ $H_2$↑

Answer:

1. Results table (completed with NR for no reaction as per above analysis):

Metals	KCl	$Fe(NO_3)_2$	$CaCl_2$	$Na_2CO_3$	HCl
Zn	NR	Zn + $Fe(NO_3)_2$ = $Zn(NO_3)_2$+Fe	NR	NR	Zn + 2HCl = $ZnCl_2$+ $H_2$↑
Mg	NR	Mg + 2$Fe(NO_3)_2$ = $Mg(NO_3)_2$+2Fe	NR	NR	Mg + 2HCl = $MgCl_2$+ $H_2$↑

1. Chemical equations as shown above for reactions and NR for no - reactions.