Question

for the last electron for s, quantum numbers values are
a n=3, l=0, m=-1, s=-1/2
b n=3, l=1, m=1, s=1/2
c n=3, l=1, m=-1, s=-1/2
d n=3, l=0, m=0, s=-1/2
continue

Explanation:

Step1: Determine the electron - configuration of sulfur

Sulfur (S) has an atomic number of 16. Its electron - configuration is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}$. The last electron is in the 3p orbital.

Step2: Identify the principal quantum number (n)

The principal quantum number (n) represents the energy level. For the 3p orbital, $n = 3$.

Step3: Identify the angular momentum quantum number (l)

For p - orbitals, the angular momentum quantum number $l=1$.

Step4: Identify the magnetic quantum number (m)

The magnetic quantum number (m) for $l = 1$ can have values $m=- 1,0,1$. In the 3p sub - shell of sulfur, according to Hund's rule, electrons are placed in different orbitals with the same spin first. The last electron is in one of the 3p orbitals, and $m$ can be $-1,0$ or $1$. Let's assume it has $m = 1$.

Step5: Identify the spin quantum number (s)

According to Hund's rule, the electrons in the 3p sub - shell have parallel spins initially. The spin quantum number $s=\frac{1}{2}$ for the last electron added to the 3p sub - shell.

Answer:

B. $n = 3, l = 1, m = 1, s=\frac{1}{2}$