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(left( \frac{1}{3} + \frac{6}{15} ight) - \frac{4}{15})

Question

(left( \frac{1}{3} + \frac{6}{15}
ight) - \frac{4}{15})

Explanation:

Step1: Simplify inside parentheses

First, find a common denominator for $\frac{1}{3}$ and $\frac{6}{15}$. The common denominator is 15, so rewrite $\frac{1}{3}$ as $\frac{5}{15}$.
$$\frac{1}{3} + \frac{6}{15} = \frac{5}{15} + \frac{6}{15} = \frac{11}{15}$$

Step2: Subtract the remaining fraction

Subtract $\frac{4}{15}$ from the result of Step1.
$$\frac{11}{15} - \frac{4}{15} = \frac{7}{15}$$

Answer:

$\frac{7}{15}$