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Question
the length of a rectangle is 8 more than the width. the area is 84 square centimeters. find the length and width of the rectangle. answer how to enter your answer (opens in new window) width = centimeters length = centimeters
Step1: Define variables
Let the width of the rectangle be $x$ cm. Then the length is $(x + 8)$ cm.
Step2: Set up area - equation
The area formula of a rectangle is $A=\text{length}\times\text{width}$. So we have $x(x + 8)=84$.
Step3: Expand and rearrange
Expand the left - hand side: $x^{2}+8x=84$. Rearrange to get a quadratic equation: $x^{2}+8x - 84 = 0$.
Step4: Factor the quadratic equation
Factor $x^{2}+8x - 84$ as $(x + 14)(x - 6)=0$.
Step5: Solve for $x$
Set each factor equal to zero: $x+14 = 0$ gives $x=-14$; $x - 6=0$ gives $x = 6$. Since the width cannot be negative, we take $x = 6$.
Step6: Find the length
The length is $x + 8$. Substitute $x = 6$ into it, we get the length is $6 + 8=14$ cm.
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Width = 6 centimeters
Length = 14 centimeters