QUESTION IMAGE
Question
lesson 1.2
practice b continued
for use with the lesson \use segments and congruence\
in the diagram, points a, b, c, and d are collinear, points c, x, y, and z are collinear, $ab = bc = cx = yz$, $ad = 54$, $xy = 22$, and $xz = 33$. find the indicated length.
- $ab$
- $bd$
- $cy$
- $cd$
- $xc$
- $cz$
find the indicated length.
- find $st$.
$\overline{rt}=32$, $\overline{rs}=4x$, $\overline{st}=12x$
- find $ac$.
$\overline{ab}=14$, $\overline{bc}=3x-4$, $\overline{ac}=4x+4$
- find $np$.
$\overline{mp}=6x-23$, $\overline{mn}=x-5$, $\overline{np}=3x+2$
point $j$ is between $h$ and $k$ on $\overline{hk}$. use the given information to write an equation in terms of $x$. solve the equation. then find $hj$ and $jk$.
- $hj = 2x$
$jk = 3x$
$kh = 25$
- $hj = \frac{x}{4}$
$jk = 3x - 4$
$kh = 22$
- $hj = 5x - 4$
$jk = 8x - 10$
$kh = 38$
- $hj = 5x - 3$
$jk = x - 9$
$kh = 5x$
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Questions 19-24
Step1: Find YZ length
$YZ = XZ - XY = 33 - 22 = 11$
Step2: Set AB = YZ
Given $AB=BC=CX=YZ$, so $AB=11$
Step3: Calculate AC length
$AC = AB + BC = 11 + 11 = 22$
Step4: Calculate CD length
$CD = AD - AC = 54 - 22 = 32$
Step5: Calculate BD length
$BD = BC + CD = 11 + 32 = 43$
Step6: Calculate CY length
$CY = CX + XY = 11 + 22 = 33$
Step7: Set XC = YZ
$XC = YZ = 11$
Step8: Calculate CZ length
$CZ = CX + XY + YZ = 11 + 22 + 11 = 44$
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Question 25
Step1: Set total length equation
$RT = RS + ST$, so $4x + 12x = 32$
Step2: Solve for x
$16x = 32 \implies x = 2$
Step3: Calculate ST length
$ST = 12x = 12 \times 2 = 24$
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Question 26
Step1: Set segment equality
$AB = 4x+4 - (3x-4) = 14$
Step2: Solve for x
$x + 8 = 14 \implies x = 6$
Step3: Calculate AC length
$AC = 4x+4 = 4\times6 +4 = 28$
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Question 27
Step1: Set segment equality
$MN = MP - NP$, so $x-5 = (6x-23)-(3x+2)$
Step2: Simplify and solve x
$x-5 = 3x-25 \implies 2x=20 \implies x=10$
Step3: Calculate NP length
$NP = 3x+2 = 3\times10 +2 = 32$
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Question 28
Step1: Set total length equation
$HJ + JK = KH$, so $2x + 3x =25$
Step2: Solve for x
$5x=25 \implies x=5$
Step3: Calculate HJ and JK
$HJ=2x=10$, $JK=3x=15$
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Question 29
Step1: Set total length equation
$\frac{x}{4} + 3x -4 =22$
Step2: Solve for x
$\frac{13x}{4}=26 \implies x=8$
Step3: Calculate HJ and JK
$HJ=\frac{8}{4}=2$, $JK=3\times8 -4=20$
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Question 30
Step1: Set total length equation
$5x-4 +8x-10=38$
Step2: Solve for x
$13x-14=38 \implies 13x=52 \implies x=4$
Step3: Calculate HJ and JK
$HJ=5\times4 -4=16$, $JK=8\times4 -10=22$
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Question 31
Step1: Set total length equation
$5x-3 +x-9=5x$
Step2: Solve for x
$6x-12=5x \implies x=12$
Step3: Calculate HJ and JK
$HJ=5\times12 -3=57$, $JK=12-9=3$
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- $AB = 11$
- $BD = 43$
- $CY = 33$
- $CD = 32$
- $XC = 11$
- $CZ = 44$
- $ST = 24$
- $AC = 28$
- $NP = 32$
- $HJ = 10$, $JK = 15$
- $HJ = 2$, $JK = 20$
- $HJ = 16$, $JK = 22$
- $HJ = 57$, $JK = 3$