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let $f(x)=4x^{2}+\\sqrt{-5x}$ evaluate $f(-5)$ -405 none -95 -395 105

Question

let $f(x)=4x^{2}+\sqrt{-5x}$
evaluate $f(-5)$
-405
none
-95
-395
105

Explanation:

Step1: Substitute $x=-5$ into $f(x)$

$f(-5)=4(-5)^2+\sqrt{-5\times(-5)}$

Step2: Calculate the squared term

$4(-5)^2=4\times25=100$

Step3: Calculate the square root term

$\sqrt{-5\times(-5)}=\sqrt{25}=5$

Step4: Sum the two results

$f(-5)=100+5$

Answer:

105