Question

level: 3 challenge 5 of 5 score: 5 start over
$4\\ nh_3 + 6\\ no \
ightarrow 5\\ n_2 + 6\\ h_2o$
4 $nh_3$
6 $no$
reactants
$n_2$ $h_2o$ $nh_3$ $no$
products leftovers
check

Explanation:

Step1: Count initial reactants

Initial: $4$ $\text{NH}_3$, $6$ $\text{NO}$

Step2: Match reaction stoichiometry

Reaction: $4\text{NH}_3 + 6\text{NO}
ightarrow 5\text{N}_2 + 6\text{H}_2\text{O}$
Reactants are used completely.

Step3: Calculate product amounts

$\text{N}_2$: $5$, $\text{H}_2\text{O}$: $6$; Leftovers: $0$ for all.

Answer:

• $\text{N}_2$: 5
• $\text{H}_2\text{O}$: 6
• Leftover $\text{NH}_3$: 0
• Leftover $\text{NO}$: 0

The product box should contain 5 $\text{N}_2$ (blue-blue molecules) and 6 $\text{H}_2\text{O}$ (blue-white molecules), with no leftover reactants.