Question

level k 〉 x.5 factor quadratics with leading co you hav
factor.
$k^{2}+8k+15$

Explanation:

Step1: Find pair of factors for 15

Look for two numbers that multiply to $15$ and add to $8$: $3$ and $5$ (since $3\times5=15$ and $3+5=8$).

Step2: Write factored form

Express the quadratic as a product of two binomials using the found numbers.

Answer:

$(k+3)(k+5)$