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liam has a bag that contains pineapple chews, cherry chews, and lime ch…

Question

liam has a bag that contains pineapple chews, cherry chews, and lime chews. he performs an experiment. liam randomly removes a chew from the bag, records the result, and returns the chew to the bag. liam performs the experiment 62 times. the results are shown below. a pineapple chew was selected 58 times. a cherry chew was selected 2 times. a lime chew was selected 2 times. based on these results, express the probability that the next chew liam removes from the bag will be cherry chew as a decimal to the nearest hundredth.

Explanation:

Step1: Calculate total number of trials

The total number of times Liam performed the experiment is the sum of the times each type of chew was selected. So, $2 + 2+58=62$ times.

Step2: Calculate probability of cherry - chew

The number of times a cherry - chew was selected is 2. The probability $P$ of an event is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So the probability of selecting a cherry - chew is $P=\frac{2}{62}=\frac{1}{31}\approx0.03$

Answer:

$0.03$