Question

this limit can now be evaluated as follows. (if an answer does not exist, enter dne.)
lim_{x
ightarrow4}\frac{x}{x + 1}=square

Explanation:

Step1: Substitute x - value

Substitute $x = 4$ into $\frac{x}{x + 1}$.
$\frac{4}{4+1}$

Step2: Simplify the fraction

Calculate the denominator and get the result.
$\frac{4}{5}$

Answer:

$\frac{4}{5}$