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line ej bisects angle ∠def. if m∠dej=5x+7 and m∠jef=8x−8. you may need …

Question

line ej bisects angle ∠def. if m∠dej=5x+7 and m∠jef=8x−8. you may need to get a piece of paper and draw this out. find x. 2 13 5 6

Explanation:

Step1: Recall angle bisector definition

Since EJ bisects \( \angle DEF \), \( m\angle DEJ = m\angle JEF \).
So, \( 5x + 7 = 8x - 8 \).

Step2: Solve for x

Subtract \( 5x \) from both sides:
\( 7 = 3x - 8 \).

Add 8 to both sides:
\( 15 = 3x \).

Divide by 3:
\( x = 5 \).

Answer:

5