Question

a line has a slope of $-\frac{1}{3}$ and passes through the point (9, 1). what is its equation in point - slope form? use the specified point in your equation. write your answer using integers, proper fractions, and improper fractions. simplify all fractions. $y-square=square(x - square)$

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.

Step2: Identify values

Given $m =-\frac{1}{3}$, $x_1 = 9$, and $y_1=1$.

Step3: Substitute values

Substitute these values into the point - slope form: $y - 1=-\frac{1}{3}(x - 9)$.

Answer:

$y - 1=-\frac{1}{3}(x - 9)$