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lines r and s are cut by a transversal. solve for x. (3x + 14)° 143°

Question

lines r and s are cut by a transversal. solve for x.
(3x + 14)° 143°

Explanation:

Step1: Set up equation using angle - relationship

Since the angles $(3x + 14)^{\circ}$ and $143^{\circ}$ are corresponding angles (assuming the lines are parallel and cut by a transversal), they are equal. So we have the equation $3x+14 = 143$.

Step2: Isolate the variable term

Subtract 14 from both sides of the equation: $3x+14 - 14=143 - 14$, which simplifies to $3x = 129$.

Step3: Solve for x

Divide both sides of the equation $3x = 129$ by 3: $\frac{3x}{3}=\frac{129}{3}$, so $x = 43$.

Answer:

$43$