Question

list 3 values that would make this inequality true.
8n + 4 ≤ 28

Explanation:

Step1: Solve the inequality for n

Subtract 4 from both sides of the inequality \(8n + 4\leq28\):
\(8n+4 - 4\leq28 - 4\)
\(8n\leq24\)
Then divide both sides by 8:
\(\frac{8n}{8}\leq\frac{24}{8}\)
\(n\leq3\)

Step2: Choose three values for n

We can choose any values of \(n\) that are less than or equal to 3. Let's pick \(n = 0\), \(n = 1\), \(n = 2\) (we could also pick 3 or negative numbers, but these are simple positive integers).

• For \(n = 0\): \(8(0)+4=4\leq28\), which is true.
• For \(n = 1\): \(8(1)+4 = 12\leq28\), which is true.
• For \(n = 2\): \(8(2)+4=20\leq28\), which is true.

Answer:

0, 1, 2 (Other valid values like 3, -1, -2 etc. are also acceptable as long as they satisfy \(n\leq3\))