Question

listed below are amounts (in millions of dollars) collected from parking meters by a security company in a certain city. a larger data - set was used to convict 5 members of the company of grand larceny. find the mean and median for each of the two samples and then compare the two sets of results. do the limited data listed here show evidence of stealing by the security companys employees?
security company: 1.5 1.1 1.5 1.1 1.4 1.3 1.7 1.3 1.3 1.2
other companies: 1.6 1.9 2.3 1.8 2.3 1.7 1.9 1.8 1.8 2.2
find the means.
the mean for the security company is $1.34 million and the mean for the other companies is $1.93 million. (type integers or decimals rounded to two decimal places as needed.)
find the medians
the median for the security company is $ million and the median for the other companies is $ million (type integers or decimals rounded to two decimal places as needed.)

Explanation:

Step1: Arrange Security Company data in ascending order

1.1, 1.2, 1.3, 1.3, 1.3, 1.4, 1.5, 1.5, 1.7
Since there are 9 data - points (an odd number), the median is the middle value.

Step2: Find the median of Security Company data

The 5th value in the ordered list is 1.3. So the median for the security company is 1.30.

Step3: Arrange Other Companies data in ascending order

1.6, 1.7, 1.8, 1.8, 1.9, 1.9, 2.2, 2.3, 2.3
Since there are 9 data - points (an odd number), the median is the middle value.

Step4: Find the median of Other Companies data

The 5th value in the ordered list is 1.90. So the median for the other companies is 1.90.

Answer:

The median for the security company is $1.30$ million and the median for the other companies is $1.90$ million.