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Question
listed below are 4 negatively charged ions (nonmetals). write the formula for the combination of the positive ions (metals) with all 4 negative ions. negative ions: s p i n a) li write the formulas for the compounds, combining li with each negative ion. 1 li₂s 2 li₃p 3 4 b) pb write the formulas for the compounds, combining pb with each negative ion. 1 2 3 4 d) fe (+2) write the formulas for the compounds, combining fe with each negative ion. 1 2 3 4 e) al write the formulas for the compounds, combining al with each negative ion. 1 2 3 4
Step1: Identify ion charges
Negative ions: $\text{S}^{2-}$, $\text{P}^{3-}$, $\text{I}^-$, $\text{N}^{3-}$; Positive ions: $\text{Li}^+$, $\text{Pb}^{2+}$, $\text{Fe}^{2+}$, $\text{Al}^{3+}$
Step2: Balance charge for Li
Cross charges to neutralize:
- $\text{Li}^+$ + $\text{S}^{2-}$ → $\text{Li}_2\text{S}$
- $\text{Li}^+$ + $\text{P}^{3-}$ → $\text{Li}_3\text{P}$
- $\text{Li}^+$ + $\text{I}^-$ → $\text{LiI}$
- $\text{Li}^+$ + $\text{N}^{3-}$ → $\text{Li}_3\text{N}$
Step3: Balance charge for Pb²⁺
Cross charges to neutralize:
- $\text{Pb}^{2+}$ + $\text{S}^{2-}$ → $\text{PbS}$
- $\text{Pb}^{2+}$ + $\text{P}^{3-}$ → $\text{Pb}_3\text{P}_2$
- $\text{Pb}^{2+}$ + $\text{I}^-$ → $\text{PbI}_2$
- $\text{Pb}^{2+}$ + $\text{N}^{3-}$ → $\text{Pb}_3\text{N}_2$
Step4: Balance charge for Fe²⁺
Cross charges to neutralize:
- $\text{Fe}^{2+}$ + $\text{S}^{2-}$ → $\text{FeS}$
- $\text{Fe}^{2+}$ + $\text{P}^{3-}$ → $\text{Fe}_3\text{P}_2$
- $\text{Fe}^{2+}$ + $\text{I}^-$ → $\text{FeI}_2$
- $\text{Fe}^{2+}$ + $\text{N}^{3-}$ → $\text{Fe}_3\text{N}_2$
Step5: Balance charge for Al³⁺
Cross charges to neutralize:
- $\text{Al}^{3+}$ + $\text{S}^{2-}$ → $\text{Al}_2\text{S}_3$
- $\text{Al}^{3+}$ + $\text{P}^{3-}$ → $\text{AlP}$
- $\text{Al}^{3+}$ + $\text{I}^-$ → $\text{AlI}_3$
- $\text{Al}^{3+}$ + $\text{N}^{3-}$ → $\text{AlN}$
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A) Li
- $\text{Li}_2\text{S}$
- $\text{Li}_3\text{P}$
- $\text{LiI}$
- $\text{Li}_3\text{N}$
B) Pb (using +2 charge, common for such compounds)
- $\text{PbS}$
- $\text{Pb}_3\text{P}_2$
- $\text{PbI}_2$
- $\text{Pb}_3\text{N}_2$
D) Fe (+2)
- $\text{FeS}$
- $\text{Fe}_3\text{P}_2$
- $\text{FeI}_2$
- $\text{Fe}_3\text{N}_2$
E) Al
- $\text{Al}_2\text{S}_3$
- $\text{AlP}$
- $\text{AlI}_3$
- $\text{AlN}$