Question

lities
n sets.
2 (2x + 4 < 8)
(\frac{b}{5} + 9 < 10)

Explanation:

Step1: Solve $2x + 4 < 8$: Subtract 4 from both sides

$2x + 4 - 4 < 8 - 4$
$2x < 4$

Step2: Divide both sides by 2

$\frac{2x}{2} < \frac{4}{2}$
$x < 2$

Step3: Solve $\frac{b}{5} + 9 < 10$: Subtract 9 from both sides

$\frac{b}{5} + 9 - 9 < 10 - 9$
$\frac{b}{5} < 1$

Step4: Multiply both sides by 5

$\frac{b}{5} \times 5 < 1 \times 5$
$b < 5$

Answer:

1. For $2x + 4 < 8$: $x < 2$
2. For $\frac{b}{5} + 9 < 10$: $b < 5$

To graph $x < 2$ on the number line: Draw an open circle at 2, then shade all values to the left of 2.