Question

long division whole number divided by who 2 1 \overline{)6 1 8}

Explanation:

Step1: Divide 61 by 21

We look at how many times 21 can go into 61. \( 21\times2 = 42 \), \( 21\times3=63 \) which is more than 61, so we use 2. Write 2 above the 1 in 618 (above the tens place of the dividend).
\( 21\times2 = 42 \)
Subtract 42 from 61: \( 61 - 42=19 \)

Step2: Bring down the 8

Bring down the 8 from the dividend to make the new number 198.

Step3: Divide 198 by 21

Now we find how many times 21 goes into 198. \( 21\times9 = 189 \), \( 21\times10 = 210 \) which is more than 198, so we use 9. Write 9 next to the 2 above the dividend (now above the ones place).
\( 21\times9=189 \)
Subtract 189 from 198: \( 198 - 189 = 9 \)

Since we have no more digits to bring down and the remainder (9) is less than the divisor (21), we stop. The quotient is 29 and the remainder is 9. If we want the decimal form, we can continue by adding a decimal point and zeros to the dividend, but for whole number long division with remainder, the result is \( 618\div21 = 29\) remainder \( 9 \), or as a decimal \( 29.\overline{428571} \) (but typically for this problem, the quotient with remainder is 29 R 9 or the decimal approximation).

Answer:

The result of \( 618\div21 \) using long division is \( 29 \) with a remainder of \( 9 \) (or as a decimal \( 29.428571\cdots \)). If we consider the quotient without remainder approximation, the integer quotient is \( 29 \) and remainder \( 9 \).