Question

8 longdiv 88, with some blank squares and a remainder r.

Explanation:

Step1: Divide the tens digit

We divide the tens digit of 88 (which is 8) by 8. Since \(8\div8 = 1\), we write 1 above the tens place. Then we multiply \(1\times8 = 8\) and subtract this from the tens digit part: \(8 - 8=0\).

Step2: Bring down the units digit

Bring down the units digit 8, so we now have 8 in the units place of the dividend part.

Step3: Divide the units digit

Divide 8 by 8. Since \(8\div8 = 1\), we write 1 above the units place. Then we multiply \(1\times8 = 8\) and subtract this from the current dividend (8): \(8 - 8 = 0\). So the remainder \(R\) is 0.

Answer:

The remainder \(R\) is \(\boldsymbol{0}\)