Question

look at the problem above and determine what a, b and c equal (the numbers have already been substituted into the quadratic formula)
a =
(type the number)
b =

Explanation:

Step1: Recall Quadratic Formula

The quadratic formula is \( \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).

Step2: Identify \( a \)

In the given expression \( \frac{-12 \pm \sqrt{(12)^2 - 4(1)(32)}}{2(1)} \), compare with the quadratic formula. The denominator is \( 2a \), here it is \( 2(1) \), so \( a = 1 \).

Step3: Identify \( b \)

The coefficient of the linear term in the formula is \( -b \), here we have \( -12 \), so \( -b=-12 \), which means \( b = 12 \).

Step4: Identify \( c \)

In the discriminant \( b^2 - 4ac \), we have \( 4(1)(32) \), so \( 4ac = 4\times1\times c \), comparing with \( 4(1)(32) \), we get \( c = 32 \).

Answer:

For \( a \): \( 1 \)
For \( b \): \( 12 \)
For \( c \): \( 32 \)