Question

1. if (mangle jkm = 43^{circ}), (mangle mkl=(8x - 20)^{circ}), and (mangle jkl=(10x - 11)^{circ}), find each measure.

x =

mangle mkl=

mangle jkl=

Explanation:

Step1: Use angle - addition postulate

$m\angle JKM + m\angle MKL=m\angle JKL$
$43+(8x - 20)=10x-11$

Step2: Simplify left - hand side

$8x + 23=10x-11$

Step3: Solve for x

$23 + 11=10x-8x$
$2x=34$
$x = 17$

Step4: Find $m\angle MKL$

$m\angle MKL=8x - 20=8\times17-20=116$

Step5: Find $m\angle JKL$

$m\angle JKL=10x - 11=10\times17-11 = 159$

Answer:

$x = 17$
$m\angle MKL=116^{\circ}$
$m\angle JKL=159^{\circ}$