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Question
maria gathered the data in the table. she finds the line of best fit to be y = 2.78x - 4.4. what is the residual value when x = 4? -6.72 -0.58 0.58 6.72
Step1: Calculate predicted y - value
When \(x = 4\), \(y_{predicted}=2.78\times4 - 4.4=11.12 - 4.4 = 6.72\)
Step2: Calculate residual
Residual \(=y_{actual}-y_{predicted}\), when \(x = 4\), \(y_{actual}=7.3\), so residual \(=7.3 - 6.72=0.58\)
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0.58