Question

1. maria is monitoring the temperature of two substances in her science lab. substance a is currently 96.2° and rising 1.5° each minute. substance b is currently 98.5° and cooling 0.8° each minute. after how many minutes will the two substances be at the same temperature? a. equation:

Explanation:

Step1: Set up the equation

Let $x$ be the number of minutes. The temperature of Substance A after $x$ minutes is $96.2 + 1.5x$. The temperature of Substance B after $x$ minutes is $98.5-0.8x$. We set them equal: $96.2 + 1.5x=98.5 - 0.8x$.

Step2: Combine like - terms

Add $0.8x$ to both sides of the equation: $96.2+1.5x + 0.8x=98.5-0.8x + 0.8x$, which simplifies to $96.2 + 2.3x=98.5$.

Step3: Isolate the variable term

Subtract 96.2 from both sides: $96.2 + 2.3x-96.2=98.5 - 96.2$, getting $2.3x=2.3$.

Step4: Solve for $x$

Divide both sides by 2.3: $\frac{2.3x}{2.3}=\frac{2.3}{2.3}$, so $x = 1$.

Answer:

1