Question

1. $2 \cdot 2^{-2}$

Explanation:

Step1: Use exponent rule \(a^m \cdot a^n = a^{m + n}\)

\(2 \cdot 2^{-2}=2^{1 + (-2)}\)

Step2: Simplify the exponent

\(2^{1 - 2}=2^{-1}\)

Step3: Use negative exponent rule \(a^{-n}=\frac{1}{a^n}\)

\(2^{-1}=\frac{1}{2^1}=\frac{1}{2}\)

Answer:

\(\frac{1}{2}\)