Question

1. $(-4i)^3 cdot 2i$

Explanation:

Step1: Expand \((-4i)^3\)

Using the power rule \((ab)^n = a^n b^n\) and \(i^3 = -i\), we have:
\((-4i)^3 = (-4)^3 \cdot i^3 = -64 \cdot (-i) = 64i\)

Step2: Multiply by \(2i\)

Now multiply \(64i\) by \(2i\):
\(64i \cdot 2i = 128i^2\)
Since \(i^2 = -1\), substitute:
\(128i^2 = 128 \cdot (-1) = -128\)

Answer:

\(-128\)