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16. 计算:$-2^{3}-|1-sqrt{2}|-sqrt3{-8}\timessqrt{(-3)^{2}}$

Question

  1. 计算:$-2^{3}-|1-sqrt{2}|-sqrt3{-8}\timessqrt{(-3)^{2}}$

Explanation:

Step1: 计算乘方与开方

$-2^3=-8$,$\sqrt{(-3)^2}=3$,$\sqrt[3]{-8}=-2$

Step2: 去绝对值符号

因为$\sqrt{2}>1$,所以$|1-\sqrt{2}|=\sqrt{2}-1$

Step3: 代入原式计算乘法

将上述结果代入,先算乘法:$-2\times3=-6$
原式变为:$-8-(\sqrt{2}-1)-(-6)$

Step4: 去括号并化简

$-8-\sqrt{2}+1+6$
合并常数项:$-8+1+6=-1$

Answer:

$-1-\sqrt{2}$