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19) $z = -2 - 2a$, for $a$ a) $a = \\frac{z + 2}{2}$ b) $a = 2z + 4$ c)…

Question

  1. $z = -2 - 2a$, for $a$

a) $a = \frac{z + 2}{2}$
b) $a = 2z + 4$
c) $a = \frac{-z - 2}{2}$
d) $a = \frac{-z + 2}{2}$

Explanation:

Step1: Isolate term with $a$

Add 2 to both sides:
$z + 2 = -2a$

Step2: Solve for $a$

Divide by $-2$:
$a = \frac{z + 2}{-2} = \frac{-z - 2}{2}$

Answer:

C) $a = \frac{-z - 2}{2}$