Question

$2x^2+3x-9$

Explanation:

Step1: Factor quadratic trinomial

We need two numbers that multiply to $2\times(-9)=-18$ and add to $3$. These numbers are 6 and -3. Split the middle term:
$2x^2 + 6x - 3x - 9$

Step2: Group and factor pairs

Group the first two and last two terms, then factor out common terms:
$2x(x + 3) - 3(x + 3)$

Step3: Factor out common binomial

Factor out $(x+3)$ from both terms:
$(2x - 3)(x + 3)$

Answer:

$(2x - 3)(x + 3)$