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$3x + 8 = 22 - 4x$ $\frac{14}{7}$ $4(3 - 2x) = 2(x + 1)$

Question

$3x + 8 = 22 - 4x$
$\frac{14}{7}$
$4(3 - 2x) = 2(x + 1)$

Explanation:

Step1: Solve first equation: collect x terms

Add $4x$ to both sides:
$3x + 4x + 8 = 22$
$7x + 8 = 22$

Step2: Isolate x term (first equation)

Subtract 8 from both sides:
$7x = 22 - 8$
$7x = 14$

Step3: Solve for x (first equation)

Divide by 7:
$x = \frac{14}{7} = 2$

Step4: Solve second equation: expand brackets

$4\times3 - 4\times2x = 2\times x + 2\times1$
$12 - 8x = 2x + 2$

Step5: Collect x terms (second equation)

Add $8x$ to both sides:
$12 = 2x + 8x + 2$
$12 = 10x + 2$

Step6: Isolate x term (second equation)

Subtract 2 from both sides:
$12 - 2 = 10x$
$10 = 10x$

Step7: Solve for x (second equation)

Divide by 10:
$x = \frac{10}{10} = 1$

Answer:

For $3x + 8 = 22 - 4x$, $x = 2$
For $4(3 - 2x) = 2(x + 1)$, $x = 1$