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4) $68 = 17x$ 6) $19v = 171$ 8) $16 + 7a=8a + 3a$ 10) $5 + 5x=x - 7$

Question

  1. $68 = 17x$
  2. $19v = 171$
  3. $16 + 7a=8a + 3a$
  4. $5 + 5x=x - 7$

Explanation:

Step1: Solve for $x$ in $68 = 17x$

Divide both sides by 17. $x=\frac{68}{17}$

Step2: Calculate the value of $x$

$x = 4$

Step3: Solve for $v$ in $19v=171$

Divide both sides by 19. $v=\frac{171}{19}$

Step4: Calculate the value of $v$

$v = 9$

Step5: Solve for $a$ in $16 + 7a=8a + 3a$

First, combine like - terms on the right side: $16+7a = 11a$. Then subtract $7a$ from both sides: $16=11a - 7a$, so $16 = 4a$. Divide both sides by 4, $a=\frac{16}{4}$

Step6: Calculate the value of $a$

$a = 4$

Step7: Solve for $x$ in $5 + 5x=x - 7$

Subtract $x$ from both sides: $5+5x - x=x - 7 - x$, which gives $5 + 4x=-7$. Then subtract 5 from both sides: $4x=-7 - 5$, so $4x=-12$. Divide both sides by 4, $x=\frac{-12}{4}$

Step8: Calculate the value of $x$

$x=-3$

Answer:

$x = 4$ (from $68 = 17x$)
$v = 9$ (from $19v = 171$)
$a = 4$ (from $16 + 7a=8a + 3a$)
$x=-3$ (from $5 + 5x=x - 7$)