Question

1. $3a^{-4}b^{4} cdot 2a^{-3}b^{0}$

Explanation:

Step1: Multiply constant coefficients

$3 \times 2 = 6$

Step2: Combine $a$-terms (add exponents)

$a^{-4} \cdot a^{-3} = a^{-4 + (-3)} = a^{-7}$

Step3: Combine $b$-terms (add exponents)

$b^{4} \cdot b^{0} = b^{4 + 0} = b^{4}$

Step4: Rewrite negative exponent (optional standard form)

$a^{-7} = \frac{1}{a^{7}}$

Answer:

$\frac{6b^{4}}{a^{7}}$ (or $6a^{-7}b^{4}$)