Question

1. $-2 \geq 4p + 6 + 4 = p \leq -3$

Explanation:

Step1: Combine constant terms

$-2 \geq 4p + (6+4)$
$-2 \geq 4p + 10$

Step2: Isolate the term with $p$

$-2 - 10 \geq 4p$
$-12 \geq 4p$

Step3: Solve for $p$

$\frac{-12}{4} \geq p$
$-3 \geq p$ or $p \leq -3$

Step4: Verify number line

A closed dot at $-3$ (since $p$ can equal $-3$) and an arrow pointing left (for values less than $-3$) matches the solution.

Answer:

The solution is $p \leq -3$, and the number line graph (closed dot at $-3$, arrow left) correctly represents this solution.