Question

6\frac{7}{9} - 5\frac{1}{3}

Explanation:

Step1: Convert mixed numbers to improper fractions

$6\frac{7}{9}=\frac{6\times9 + 7}{9}=\frac{54 + 7}{9}=\frac{61}{9}$
$5\frac{1}{3}=\frac{5\times3 + 1}{3}=\frac{15 + 1}{3}=\frac{16}{3}$

Step2: Find a common denominator for subtraction

The common denominator of 9 and 3 is 9. So we convert $\frac{16}{3}$ to a fraction with denominator 9:
$\frac{16}{3}=\frac{16\times3}{3\times3}=\frac{48}{9}$

Step3: Subtract the two fractions

$\frac{61}{9}-\frac{48}{9}=\frac{61 - 48}{9}=\frac{13}{9}$

Step4: Convert the improper fraction back to a mixed number (optional)

$\frac{13}{9}=1\frac{4}{9}$

Answer:

$1\frac{4}{9}$ (or $\frac{13}{9}$)