QUESTION IMAGE
Question
- $y < |x - 5|$
$2x - y > 1$
- $y < |x - 2|$
$y > 2x - 4$
9)
Problem 7: $y < |x-5|$ and $2x - y > 1$
Step1: Rewrite inequalities
$y < |x-5|$; $y < 2x - 1$
Step2: Graph $y=|x-5|$
This is a V-shaped graph with vertex at $(5,0)$, opening upwards. Draw it as a dashed line, shade below the line (since $y < |x-5|$).
Step3: Graph $y=2x-1$
This is a line with slope $2$, y-intercept $(0,-1)$. Draw it as a dashed line, shade below the line (since $y < 2x-1$).
Step4: Find intersection
Solve $|x-5|=2x-1$:
- Case 1: $x\geq5$: $x-5=2x-1 \implies x=-4$ (invalid, not $\geq5$)
- Case 2: $x<5$: $5-x=2x-1 \implies 3x=6 \implies x=2$, $y=2(2)-1=3$. Intersection at $(2,3)$.
Step5: Identify solution region
The overlapping shaded area is the solution: below both dashed lines, bounded by the V-shape and the straight line, with the intersection at $(2,3)$.
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Problem 8: $y < |x-2|$ and $y > 2x - 4$
Step1: Rewrite inequalities
$y < |x-2|$; $y > 2x - 4$
Step2: Graph $y=|x-2|$
V-shaped graph with vertex at $(2,0)$, opening upwards. Draw as dashed line, shade below the line.
Step3: Graph $y=2x-4$
Line with slope $2$, y-intercept $(0,-4)$. Draw as dashed line, shade above the line (since $y > 2x-4$).
Step4: Find intersections
Solve $|x-2|=2x-4$:
- Case1: $x\geq2$: $x-2=2x-4 \implies x=2$, $y=0$. Intersection at $(2,0)$.
- Case2: $x<2$: $2-x=2x-4 \implies 3x=6 \implies x=2$ (invalid, not $<2$).
Find where $2x-4$ meets the left arm of the V: $2-x=2x-4$ gives the same $x=2$, so check another point: when $x=0$, $|0-2|=2$, $2(0)-4=-4$, so the region is between the line and the V-shape.
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For Problem 7:
- The solution is the overlapping shaded area below the dashed V-shaped graph $y=|x-5|$ and below the dashed line $y=2x-1$, with the boundary intersection at $(2,3)$.
For Problem 8:
- The solution is the overlapping shaded area below the dashed V-shaped graph $y=|x-2|$ and above the dashed line $y=2x-4$, with the boundary intersection at $(2,0)$.
(Note: To complete the task fully, plot the dashed lines and shade the overlapping regions on the provided coordinate grids as described.)