Question

73.
\frac{4}{5} +
\frac{3}{5} +
\frac{2}{5}

Explanation:

Step1: Identify the operation

We need to add the fractions \(\frac{4}{5}\), \(\frac{3}{5}\), and \(\frac{2}{5}\). Since they have the same denominator, we can add the numerators directly.

Step2: Add the numerators

The formula for adding fractions with the same denominator is \(\frac{a}{c}+\frac{b}{c}+\frac{d}{c}=\frac{a + b + d}{c}\). Here, \(a = 4\), \(b = 3\), \(d = 2\), and \(c = 5\). So we calculate \(4+3 + 2\) in the numerator.
\(4+3+2=9\)

Step3: Form the result

Putting the sum of the numerators over the common denominator, we get \(\frac{9}{5}\), which can also be written as \(1\frac{4}{5}\) or \(1.8\). But let's check the original problem again. Wait, maybe there was a miswriting. Wait, the first number looks like "7.3" but then the fractions. Wait, maybe the problem is \(\frac{4}{5}+\frac{3}{5}+\frac{2}{5}\)? Let's assume that. So adding the numerators: \(4 + 3+2=9\), so \(\frac{9}{5}=1.8\). But if the first number is 7.3, maybe it's a different problem. Wait, the user's image shows "7.3" and then \(\frac{4}{5}+\frac{3}{5}+\frac{2}{5}\). Maybe it's a typo. Let's proceed with the fraction addition.

Answer:

If we consider the fraction addition \(\frac{4}{5}+\frac{3}{5}+\frac{2}{5}\), the sum is \(\frac{9}{5}\) (or \(1.8\) or \(1\frac{4}{5}\)). If there was a misinterpretation and the first number is part of it, maybe the problem is \(7.3+\frac{4}{5}+\frac{3}{5}+\frac{2}{5}\). Let's calculate that. First, convert the fractions to decimals: \(\frac{4}{5}=0.8\), \(\frac{3}{5}=0.6\), \(\frac{2}{5}=0.4\). Then add them to 7.3: \(7.3 + 0.8+0.6 + 0.4=7.3+(0.8 + 0.6+0.4)=7.3 + 1.8 = 9.1\). But the original image is a bit unclear. Assuming the fractions are to be added: \(\frac{4}{5}+\frac{3}{5}+\frac{2}{5}=\frac{9}{5}=1.8\) or \(1\frac{4}{5}\). If including 7.3, then \(7.3 + 1.8=9.1\). But based on the fractions alone, the sum is \(\frac{9}{5}\) (or \(1.8\)).