Question

(9) $sqrt{18} cdot sqrt{24}$

Explanation:

Step1: Rewrite radicands as factors

$\sqrt{18} = \sqrt{9 \times 2} = 3\sqrt{2}$, $\sqrt{24} = \sqrt{4 \times 6} = 2\sqrt{6}$

Step2: Multiply the simplified radicals

$3\sqrt{2} \times 2\sqrt{6} = (3 \times 2) \times \sqrt{2 \times 6}$

Step3: Simplify the product

$6 \times \sqrt{12} = 6 \times 2\sqrt{3} = 12\sqrt{3}$

Answer:

$12\sqrt{3}$