Question

a. -4 b. 4 c. $-\frac{1}{4}$ d. $\frac{1}{4}$

Explanation:

Step1: Recall slope formula

The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is \( m = \frac{y_2 - y_1}{x_2 - x_1} \).

Step2: Identify points

Let \((x_1, y_1) = (-1, 8)\) and \((x_2, y_2) = (2, -4)\).

Step3: Substitute into formula

\( m = \frac{-4 - 8}{2 - (-1)} = \frac{-12}{3} = -4 \)? Wait, no, wait. Wait, the first point: looking at the graph, the first point is \((-1, 8)\)? Wait, no, the user's graph: (-1, 8)? Wait, the y-axis: the first blue dot is (-1, 8)? Wait, no, the y-axis has 10, then maybe the first point is (-1, 8) and (2, -4). Wait, let's recalculate. \( y_2 - y_1 = -4 - 8 = -12 \), \( x_2 - x_1 = 2 - (-1) = 3 \), so \( m = \frac{-12}{3} = -4 \)? But wait, that's option A? Wait, no, maybe I misread the points. Wait, maybe the first point is (-1, 8) and (2, -4). Wait, but let's check again. Wait, the slope formula is \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Let's take (x1, y1) = (-1, 8) and (x2, y2) = (2, -4). Then \( y_2 - y_1 = -4 - 8 = -12 \), \( x_2 - x_1 = 2 - (-1) = 3 \), so \( m = \frac{-12}{3} = -4 \). Wait, but option A is -4? Wait, but let me check again. Wait, maybe the points are (-1, 8) and (2, -4). So slope is ( -4 - 8 ) / (2 - (-1)) = -12/3 = -4. So the slope is -4, which is option A.

Wait, but wait, maybe I made a mistake. Let's confirm the points. The graph has (-1, 8) and (2, -4). So using slope formula: \( m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 - 8}{2 - (-1)} = \frac{-12}{3} = -4 \). So the slope is -4, which is option A.

Answer:

A. -4