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c $3(x + 4) = \\frac{1}{3}(6 + 12x)$

Question

c $3(x + 4) = \frac{1}{3}(6 + 12x)$

Explanation:

Step1: Expand both sides

$3x + 12 = \frac{1}{3} \times 6 + \frac{1}{3} \times 12x$
$3x + 12 = 2 + 4x$

Step2: Isolate x terms

$3x - 4x = 2 - 12$

Step3: Simplify to solve for x

$-x = -10$
$x = 10$

Answer:

$x = 10$