Question

divide.
$\frac{2x^{2}+13x + 9}{x + 7}$
$?x+square+\frac{square}{x + 7}$

Explanation:

Step1: Divide leading terms

$\frac{2x^2}{x} = 2x$

Step2: Multiply divisor by result

$2x(x+7) = 2x^2 + 14x$

Step3: Subtract from dividend

$(2x^2+13x+9)-(2x^2+14x) = -x + 9$

Step4: Divide new leading term

$\frac{-x}{x} = -1$

Step5: Multiply divisor by result

$-1(x+7) = -x -7$

Step6: Subtract to get remainder

$(-x+9)-(-x-7) = 16$

Answer:

$2x + (-1) + \frac{16}{x+7}$ (or simplified: $2x - 1 + \frac{16}{x+7}$)
The missing values are 2, -1, and 16 respectively.