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$\\frac{1}{6}c + 20 = 33$

Question

$\frac{1}{6}c + 20 = 33$

Explanation:

Step1: Subtract 20 from both sides

$\frac{1}{6}c + 20 - 20 = 33 - 20$
$\frac{1}{6}c = 13$

Step2: Multiply both sides by 6

$6\times\frac{1}{6}c = 13\times6$
$c = 78$

Answer:

$c = 78$