Question

$\frac{2ba^{2}}{(3b^{2})^{3}}$

Explanation:

Step1: Simplify denominator exponent

$(3b^2)^3 = 3^3 \cdot (b^2)^3 = 27b^6$

Step2: Rewrite the fraction

$\frac{2ba^2}{27b^6}$

Step3: Cancel common b terms

$\frac{2a^2}{27b^{6-1}} = \frac{2a^2}{27b^5}$

Answer:

$\frac{2a^2}{27b^5}$