Question

$\frac{2xy^{-3}}{3yx^{-3}}$

Explanation:

Step1: Rewrite negative exponents

Recall that $a^{-n}=\frac{1}{a^n}$ and $\frac{1}{a^{-n}}=a^n$. Rewrite the expression:
$\frac{2xy^{-3}}{3yx^{-3}} = \frac{2x \cdot x^{3}}{3y \cdot y^{3}}$

Step2: Combine like terms

Use exponent rule $a^m \cdot a^n = a^{m+n}$:
$\frac{2x^{1+3}}{3y^{1+3}} = \frac{2x^{4}}{3y^{4}}$

Answer:

$\frac{2x^4}{3y^4}$