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QUESTION IMAGE

$-\frac{5^{2}}{4}+3(5)+7 =$

Question

$-\frac{5^{2}}{4}+3(5)+7 =$

Explanation:

Step1: Calculate the exponent

First, we calculate \(5^2\), which is \(5\times5 = 25\). So the expression becomes \(-\frac{25}{4}+3(5)+7\).

Step2: Calculate the multiplication

Next, we calculate \(3(5)=15\). Now the expression is \(-\frac{25}{4}+15 + 7\).

Step3: Add the integers

Then, we add \(15\) and \(7\), which gives \(15 + 7=22\). So the expression is now \(-\frac{25}{4}+22\).

Step4: Convert to common denominator

To add these two terms, we convert \(22\) to a fraction with denominator \(4\). \(22=\frac{88}{4}\). So the expression becomes \(-\frac{25}{4}+\frac{88}{4}\).

Step5: Add the fractions

Finally, we add the two fractions: \(\frac{- 25+88}{4}=\frac{63}{4}=15.75\).

Answer:

\(\frac{63}{4}\) (or \(15.75\))