Question

(\frac{5c^{2}d^{3}}{-4c^{2}d})

Explanation:

Step1: Cancel common terms

Cancel $c^2d$ from numerator and denominator.
$\frac{5c^2d^3}{-4c^2d} = \frac{5d^{3-1}}{-4}$

Step2: Simplify exponent of d

Calculate $d^{3-1}=d^2$.
$\frac{5d^2}{-4}$

Step3: Rewrite in standard form

Place negative sign in front of fraction.
$-\frac{5d^2}{4}$

Answer:

$-\frac{5d^2}{4}$