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Question
$\frac{6}{8} \div \frac{3}{9} =$
- $\frac{3}{7} \div \frac{5}{12} =$
First Problem: $\boldsymbol{\frac{6}{8} \div \frac{3}{9}}$
Step1: Recall division of fractions rule
To divide fractions, multiply by the reciprocal: $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$. So, $\frac{6}{8} \div \frac{3}{9} = \frac{6}{8} \times \frac{9}{3}$.
Step2: Simplify and multiply
Simplify $\frac{9}{3}=3$ and $\frac{6}{8}=\frac{3}{4}$. Then multiply: $\frac{3}{4} \times 3 = \frac{9}{4}$.
Step1: Apply fraction division rule
Using $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$, we get $\frac{3}{7} \div \frac{5}{12} = \frac{3}{7} \times \frac{12}{5}$.
Step2: Multiply numerators and denominators
Multiply numerators: $3 \times 12 = 36$; multiply denominators: $7 \times 5 = 35$. So, $\frac{36}{35}$.
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$\frac{9}{4}$ (or $2\frac{1}{4}$)