Question

(\frac{7}{3}+\frac{4}{5}-\frac{1}{15})

Explanation:

Step1: Find common denominator (15)

Rewrite fractions: $\frac{7}{3} = \frac{35}{15}$, $\frac{4}{5} = \frac{12}{15}$, $\frac{1}{15}$ stays as is.

Step2: Substitute and compute

$\frac{35}{15} + \frac{12}{15} - \frac{1}{15} = \frac{35+12-1}{15}$

Step3: Simplify numerator

$35+12-1=46$, so $\frac{46}{15}$

Answer:

$\frac{46}{15}$ or $3\frac{1}{15}$