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Question
$\frac{n^{-8}}{n^{-7}}$
Step1: Apply exponent division rule
When dividing terms with the same base, subtract the exponents: $\frac{n^a}{n^b}=n^{a-b}$
Here, $a=-8$ and $b=-7$, so the expression becomes $n^{-8 - (-7)}$
Step2: Simplify the exponent
Calculate the value of the exponent: $-8 - (-7) = -8 + 7 = -1$
So the expression simplifies to $n^{-1}$
Step3: Rewrite negative exponent
A negative exponent means the reciprocal: $n^{-1}=\frac{1}{n}$
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$\frac{1}{n}$ or $n^{-1}$