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Question
\\(\frac{x}{-7} + 1 = 8\\)
\\(x = \square\\)
Step1: Subtract 1 from both sides
$\frac{x}{-7} + 1 - 1 = 8 - 1$
Simplifies to: $\frac{x}{-7} = 7$
Step2: Multiply both sides by -7
$\frac{x}{-7} \times (-7) = 7 \times (-7)$
Simplifies to: $x = -49$
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-49