QUESTION IMAGE
Question
i 177b (4) (7) (5) (8) (6) (9)
Step1: Recall 30 - 60 - 90 triangle ratio
In a 30 - 60 - 90 triangle, the sides are in the ratio $1:\sqrt{3}:2$. If the side opposite the 30 - degree angle is $a$, the side opposite the 60 - degree angle is $a\sqrt{3}$, and the hypotenuse is $2a$.
Step2: Solve for (4)
The side opposite the 60 - degree angle is $5\sqrt{3}$. Let the side opposite the 30 - degree angle be $a$. Since the side opposite the 60 - degree angle is $a\sqrt{3}$, then $a\sqrt{3}=5\sqrt{3}$, so $a = 5$. The hypotenuse $x=2a = 10$.
Step3: Solve for (5)
The hypotenuse is 6. Since the hypotenuse in a 30 - 60 - 90 triangle is $2a$, then $2a = 6$, so $a = 3$. The side opposite the 30 - degree angle $x=a = 3$.
Step4: Solve for (6)
The side opposite the 60 - degree angle is $3\sqrt{3}$. Since the side opposite the 60 - degree angle is $a\sqrt{3}$, then $a\sqrt{3}=3\sqrt{3}$, so $a = 3$. The side opposite the 30 - degree angle $x=a = 3$.
Step5: Solve for (7)
The side opposite the 30 - degree angle is 3. Since the hypotenuse in a 30 - 60 - 90 triangle is $2a$, and here $a = 3$, the hypotenuse $x=2a=6$.
Step6: Solve for (8)
The side opposite the 60 - degree angle is 2. Since the side opposite the 60 - degree angle is $a\sqrt{3}$, then $a\sqrt{3}=2$, so $a=\frac{2}{\sqrt{3}}$. The hypotenuse $x = 2a=\frac{4}{\sqrt{3}}=\frac{4\sqrt{3}}{3}$.
Step7: Solve for (9)
The side opposite the 30 - degree angle is $3\sqrt{6}$. Since the side opposite the 60 - degree angle $x$ in a 30 - 60 - 90 triangle is $a\sqrt{3}$ and the side opposite 30 - degree angle is $a$, here $a = 3\sqrt{6}$, so $x=a\sqrt{3}=3\sqrt{6}\times\sqrt{3}=9\sqrt{2}$.
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(4) $x = 10$
(5) $x = 3$
(6) $x = 3$
(7) $x = 6$
(8) $x=\frac{4\sqrt{3}}{3}$
(9) $x = 9\sqrt{2}$