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Question
i. \\(\log_{8} 27 - \log_{8} x = \log_{8} 3\\)
Step1: Apply log subtraction rule
$\log_{8}\frac{27}{x} = \log_{8}3$
Step2: Equate arguments of logs
$\frac{27}{x} = 3$
Step3: Solve for x
$x = \frac{27}{3} = 9$
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$x=9$